x^2-44x+20=0

Solution for x^2-44x+20=0 equation:

x^2-44x+20=0

a = 1; b = -44; c = +20;
Δ = b2-4ac
Δ = -442-4·1·20
Δ = 1856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1856}=\sqrt{64*29}=\sqrt{64}*\sqrt{29}=8\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-8\sqrt{29}}{2*1}=\frac{44-8\sqrt{29}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+8\sqrt{29}}{2*1}=\frac{44+8\sqrt{29}}{2}
$